392v^2=32

Solution for 392v^2=32 equation:

392v^2=32

We move all terms to the left:

392v^2-(32)=0

a = 392; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·392·(-32)
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-224}{2*392}=\frac{-224}{784}
=-2/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+224}{2*392}=\frac{224}{784}
=2/7
$